http://blinkenlight.livejournal.com/ ([identity profile] blinkenlight.livejournal.com) wrote in [community profile] useless_faq 2006-03-07 12:26 pm (UTC)

Ну да, примерно так. 600 нм это ближе к красному, поэтому получится что-то типа (в произвольных единицах) y(R)=1, y(G)=.2, y(B)=0.

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